Binary Tree Level Order Traverse
2026. 3. 15. 10:12ㆍAlgorithm/Leetcode, Lintcode, HackerRank, etc.
- 목차
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# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def levelOrderBottom(self, root: Optional[TreeNode]) -> List[List[int]]:
if not root:
return []
q = collections.deque([root])
res = []
while q:
nq = collections.deque()
line = []
while q:
cur = q.popleft()
if not cur:
continue
line += cur.val,
if cur.left:
nq += cur.left,
if cur.right:
nq += cur.right,
res.insert(0, line)
q = nq
return res
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